1Z1-071 LATEST TEST PDF - REAL 1Z1-071 EXAM QUESTIONS

1z1-071 Latest Test Pdf - Real 1z1-071 Exam Questions

1z1-071 Latest Test Pdf - Real 1z1-071 Exam Questions

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Oracle Database SQL Sample Questions (Q62-Q67):

NEW QUESTION # 62
View the exhibit and examine the structure of the CUSTOMERS table.

Which two tasks would require subqueries or joins to be executed in a single statement? (Choose two.)

  • A. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
  • B. finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers
  • C. finding the number of customers, in each city, whose marital status is 'married'.
  • D. listing of those customers, whose credit limit is the same as the credit limit of customers residing in the city 'Tokyo'.
  • E. listing of customers who do not have a credit limit and were born before 1980

Answer: B,D


NEW QUESTION # 63
The CUSTOMERStable has a CUST_CREDIT_LIMITcolumn of data type NUMBER.
Which two queries execute successfully? (Choose two.)

  • A. Available') FROM customers;
    SELECT NVL2 (cust_credit_limit * .15, 'Not Available') FROM customers;
  • B. SELECT NVL (cust_credit_limit * .15, 'Not Available') FROM customers;
  • C. SELECT NVL(TO_CHAR(cust_credit_limit * .15), 'Not Available') FROM customers;
  • D. SELECT TO_CHAR(NVL(cust_credit_limit * .15, 'Not Available')) FROM customers;
  • E. SELECT NVL2(cust_credit_limit, TO_CHAR(cust_credit_limit * .15), 'Not

Answer: A,C


NEW QUESTION # 64
Which statement adds a column called SALARYto the EMPLOYEEStable having 100 rows, which cannot contain null?
ALTER TABLE EMPLOYEES

  • A. ADD SALARY NUMBER(8,2) DEFAULT CONSTRAINT p_nn NOT NULL;
    ALTER TABLE EMPLOYEES
  • B. ADD SALARY NUMBER(8,2) DEFAULT NOT NULL;
    ALTER TABLE EMPLOYEES
  • C. ADD SALARY NUMBER(8,2) NOT NULL;
  • D. ADD SALARY NUMBER(8,2) DEFAULT 0 NOT NULL;
    ALTER TABLE EMPLOYEES

Answer: B


NEW QUESTION # 65
View the Exhibit and examine the structure of the ORDER_ITEMS table. (Choose the best answer.)

You must select the ORDER_ID of the order that has the highest total value among all the orders in the ORDER_ITEMS table.
Which query would produce the desired result?

  • A. SELECT order_idFROM order_itemsGROUP BY order_idHAVING
    SUM(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity))FROM order_items GROUP BY order_id);
  • B. SELECT order_idFROM order_itemsWHERE (unit_price*quantity) = (SELECT MAX(unit_price*quantity)FROM order_itemsGROUP BY order_id)
  • C. SELECT order_idFROM order_itemsWHERE(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity)FROM order_items) GROUP BY order_id);
  • D. SELECT order_idFROM order_itemsWHERE(unit_price*quantity)
    MAX(unit_price*quantity)GROUP BY order_id);

Answer: A


NEW QUESTION # 66
Examine the description of the PRODUCTS table:

Which three queries use valid expressions?

  • A. SELECT product_id, (unit_price * 0.15 / (4.75 + 552.25)) FROM products;
  • B. SELECT ptoduct_id, (expiry_date-delivery_date) * 2 FROM products;
  • C. SELECT product_id,unit_price || "Discount", unit_price + surcharge-discount FROM products;
  • D. SPLECT product_id, expiry_date * 2 FROM products;
  • E. SELECT produet_id, unit_pricer, 5 "Discount",unit_price+surcharge-discount FROM products;
  • F. SELEGT product_id, unit_price, unit_price + surcharge FROM products;

Answer: A,B,F


NEW QUESTION # 67
......

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